SQL EXISTS() 函数
sql exists() 函数
exists 运算符用于判断查询子句是否有记录,如果有一条或多条记录存在返回 true,否则返回 false。
1. exists() 语法
select column_name(s) from table_name where exists (select column_name from table_name where condition);
样本数据库
在本教程中,我们将使用 yapf 样本数据库。
下面是选自 "websites" 表的数据:
+----+--------------+---------------------------+-------+---------+ | id | name | url | alexa | country | +----+--------------+---------------------------+-------+---------+ | 1 | google | https://www.google.cm/ | 1 | usa | | 2 | 淘宝 | https://www.taobao.com/ | 13 | cn | | 3 | 硕编程 | http://www.yapf.com/ | 4689 | cn | | 4 | 微博 | http://weibo.com/ | 20 | cn | | 5 | facebook | https://www.facebook.com/ | 3 | usa | +----+---------------+---------------------------+-------+---------+
下面是 "access_log" 网站访问记录表的数据:
+-----+---------+-------+------------+ | aid | site_id | count | date | +-----+---------+-------+------------+ | 1 | 1 | 45 | 2016-05-10 | | 2 | 3 | 100 | 2016-05-13 | | 3 | 1 | 230 | 2016-05-14 | | 4 | 2 | 10 | 2016-05-14 | | 5 | 5 | 205 | 2016-05-14 | | 6 | 4 | 13 | 2016-05-15 | | 7 | 3 | 220 | 2016-05-15 | | 8 | 5 | 545 | 2016-05-16 | | 9 | 3 | 201 | 2016-05-17 | +-----+---------+-------+------------+
2. exists() 范例
现在我们想要查找总访问量(count 字段)大于 200 的网站是否存在。
select websites.name, websites.country from websites where exists (select count from access_log where websites.id = access_log.site_id and count > 200); 执行结果: +---------------+-------------+ | name | country | +---------------+-------------+ | google | usa | | 硕编程 | cn | | facebook | usa | +---------------+-------------+
exists 可以与 not 一同使用,查找出不符合查询语句的记录:
select websites.name, websites.country from websites where not exists (select count from access_log where websites.id = access_log.site_id and count > 200); 执行结果: +---------------+-------------+ | name | country | +---------------+-------------+ | 淘宝 | cn | | 微博 | cn | +---------------+-------------+