C 语言实例 – 判断Armstrong数(阿姆斯壮数)

C 语言实例 - 判断Armstrong数(阿姆斯壮数)

C 语言实例 C 语言实例

Armstrong 数,就是n位数的各位数的n次方之和等于该数,如:

153=1^3+5^3+3^3
1634=1^4+6^4+3^4+4^4

实例

#include <stdio.h> int main() { int number, originalNumber, remainder, result = 0; printf("输入三位数: "); scanf("%d", &number); originalNumber = number; while (originalNumber != 0) { remainder = originalNumber%10; result += remainder*remainder*remainder; originalNumber /= 10; } if(result == number) printf("%d 是 Armstrong 数",number); else printf("%d 不是 Armstrong 数",number); return 0; }

运行结果:

输入三位数: 371
371 是 Armstrong 

实例 - 两数之间的 Armstrong 数

#include <stdio.h> #include <math.h> int main() { int low, high, i, temp1, temp2, remainder, n = 0, result = 0; printf("输入两个整数: "); scanf("%d %d", &low, &high); printf("%d 和 %d 之间的 Armstrong 数为: ", low, high); for(i = low + 1; i < high; ++i) { temp2 = i; temp1 = i; // 计算 while (temp1 != 0) { temp1 /= 10; ++n; } while (temp2 != 0) { remainder = temp2 % 10; result += pow(remainder, n); temp2 /= 10; } if (result == i) { printf("%d ", i); } n = 0; result = 0; } return 0; }

运行结果:

输入两个整数: 100 1000
100 和 1000 之间的 Armstrong 数为: 153 370 371 407

实例 - 使用函数判断Armstrong 数

#include <stdio.h> #include <math.h> int checkPrimeNumber(int n); int checkArmstrongNumber(int n); int main() { int n, flag; printf("输入正整数: "); scanf("%d", &n); // 检测素数 flag = checkPrimeNumber(n); if (flag == 1) printf("%d 是素数。\n", n); else printf("%d 不是素数\n", n); // 检测 Armstrong 数 flag = checkArmstrongNumber(n); if (flag == 1) printf("%d 是 Armstrong 数。", n); else printf("%d 不是 Armstrong 数。",n); return 0; } int checkPrimeNumber(int n) { int i, flag = 1; for(i=2; i<=n/2; ++i) { // 非素数条件 if(n%i == 0) { flag = 0; break; } } return flag; } int checkArmstrongNumber(int number) { int originalNumber, remainder, result = 0, n = 0, flag; originalNumber = number; while (originalNumber != 0) { originalNumber /= 10; ++n; } originalNumber = number; while (originalNumber != 0) { remainder = originalNumber%10; result += pow(remainder, n); originalNumber /= 10; } // 判断条件 if(result == number) flag = 1; else flag = 0; return flag; }

输出结果为:

输入正整数: 371
371 不是素数
371 是 Armstrong 数。

C 语言实例 C 语言实例

相关文章